150k views
5 votes

z = 3 + i \\ {z}^(5) =??


User Sneaksta
by
7.3k points

1 Answer

4 votes

Answer:


z^(5) = - 12 + 316 i

Explanation:

Given that -

z = 3 + i


z^(2) =
( 3 + i )^(2)


z^(2) = 9 +
i^(2) + 6 i


z^(2) = 9 - 1 + 6 i


z^(2) = 8 + 6 i


z^(3) =
z^(2) × z


z^(3) = ( 8 + 6 i ) × ( 3 + i )


z^(3) = 24 + 8 i + 18 i + 6 i²


z^(3) = 24 + 26 i - 6


z^(3) = 18 + 26 i


z^(5) =
z^(2) ×
z^(3)


z^(5) = ( 8 + 6 i ) × ( 18 + 26 i )


z^(5) = 144 + 208 i + 108 i + 156 i²


z^(5) = 144 + 316 i -156


z^(5) = - 12 + 316 i

User Seulgi
by
7.4k points