Question

An experiment is conducted using nitrogen monoxide and bromine reacted to form nitrosyl bromide. Calculate Keq for the reaction using the following equation data. [NOBr] = 0.0474 mol/L [NO] = 0.312 mol/L [Br2] = 0.259 mol/L Keq =

Answer 1

The equilibrium coefficient of the reaction is 0.0891.

Step-by-step explanation:

The balanced chemical reaction from the given data is as follows.

`2NO+Br_(2)\rightarrow 2NOBr`

`K_(eq)=([NOBr]^(2))/([NO]^(2)[Br_(2)])`

From the given data,

[NOBr] = 0.0474 mol/L

[NO] = 0.312 mol/L

`[Br_(2)]=0.259 mol/L`

Substitute the all given values into the
`K_(eq)` formula.

`K_(eq)=((0.0474)^(2))/((0.312)^(2)(0.259))=0.0891`

Therefore, The equilibrium coefficient of the reaction is 0.0891.