Answer:
The Kinetic energy of the 6kg cart moving at a speed of 2 m/s at the bottom of the ramp is 12 J
Step-by-step explanation:
Given:
Mass of the cart = 6 kg
Speed with which the cart is moving = 2 m/s
To Find:
The Kinetic Energy = ?
Solution:
The Kinetic Energy of the object is given,
![K.E= (1)/(2) m v ^2](https://img.qammunity.org/2020/formulas/biology/middle-school/ks8lk5pj7o65yy8ptighkklf83kbwa6uc7.png)
where
m is the mass of the object
v is the velocity of the object
Now substituting the given values
The Kinetic energy of the 6kg cart moving at a speed of 2 m/s is
![= (1)/(2) m v ^2](https://img.qammunity.org/2020/formulas/biology/middle-school/esp0q4umu8xrmy59k6nas3hq80p6kpuwsk.png)
![= (1)/(2) (6) (2)^2](https://img.qammunity.org/2020/formulas/biology/middle-school/5ib3esj7l4q63wvxahabsey7zt46ik0gpd.png)
![= (1)/(2) (6)(4)](https://img.qammunity.org/2020/formulas/biology/middle-school/x654nja8rt6mq4qzec9ahzcplzh07zomen.png)
![= (1)/(2)* (24)](https://img.qammunity.org/2020/formulas/biology/middle-school/jep7d7tln16us1v59lm2czt8nnlirasleq.png)
![= (24)/(2)](https://img.qammunity.org/2020/formulas/biology/middle-school/ad4rrci8l9nyq5bg83ikbziu2a7qlilz2s.png)
= 12 J