The Question has missing figure. The figure is in the attachment.
Answer:
The Area of the figure is
.
Explanation:
The given figure is composed of a rectangle and a triangle.
So ABCDE is a pentagon in which ABDE is a rectangle and BCD is atriangle.
Length of AB = 4.8
Length of AE = 9.6
Now draw a line segment from C to AE that is Point M on AE.
So, Length of AM = 9
![\therefore Height\ of\ triangle=9-4.8=4.2](https://img.qammunity.org/2020/formulas/mathematics/high-school/qmmvc7el8ekmu7v6857gk2eo28o1re4dcu.png)
Now,
Area of rectangle =
![length* width](https://img.qammunity.org/2020/formulas/mathematics/college/ar5g8xbscz25h3qij4l7lcxfi2ficekvva.png)
![Area\ of\ rectangle = 9.6*4.8 = 46.08\ units^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/zf0tzcdngk589sib371iim6sh0g4xwtdf1.png)
Area of Triangle =
![(1)/(2)* base* height](https://img.qammunity.org/2020/formulas/mathematics/middle-school/g43fatbacblh2va1h393wrhv45lrn1hya6.png)
![Area\ of\ triangle =(1)/(2)*9.6* 4.2=20.16\ units^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/eu0gyp221zxzktxjujbyzqmxt8xggw4bt9.png)
Thus area of figure=Area of rectangle+Area of Triangle
Area of the figure =
![46.08+20.16=66.24\ units^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/9gq35fzw5hhh4vr34an9l8wnapcj1i4cjb.png)
Round to the nearest is 66.2 sq. units.
Hence The Area of the figure is
.