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Suppose h(x)=2x^2+x-7 solve h(x)=8​

Suppose h(x)=2x^2+x-7 solve h(x)=8​
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Suppose h(x)=2x^2+x-7 solve h(x)=8​

User Heru
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1 Answer

2 votes
X = {-3, 5/2}

You have to subtract 8 from both sides then factor the trinomial into two binomials
Suppose h(x)=2x^2+x-7 solve h(x)=8​-example-1
User YetAnotherRandomUser
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