Question

- A person is on an elevator that moves

downward with an acceleration of
1.8 m/s ?. If the person weighs 686 N,
what is the net force on the person?

Answer 1

The net force on the person is 126 N.

Step-by-step explanation:

In this question, we are given that a person is on an elevator that moves downward with an acceleration of 1.8 m/s² and the person weighs 686 N. We need to determine the net force on the person.

To find the net force, we can use Newton's second law, which states that the net force is equal to the mass of the object multiplied by its acceleration. In this case, the mass of the person can be found by dividing the weight (686 N) by the acceleration due to gravity (9.8 m/s²).

So, mass = weight/acceleration due to gravity = 686 N/9.8 m/s² = 70 kg.

Now, we can calculate the net force using Newton's second law: Fnet = ma = 70 kg * 1.8 m/s² = 126 N.

The net force on the person is 126 Newtons (N).

Answer 2

The net force acting on the person is, F = 560 N

Step-by-step explanation:

Given data,

The downward acceleration of the elevator, a = 1.8 m/s²

The weight of the person is, W = mg

= 686 N

Therefore the mass of the person,

m = W /g

= 686 / 9.8

= 70 kg

The net force acting on the person,

F = mg - ma

= 686 - 70 x 1.8

= 560 N

Hence, the net force acting on the person is, F = 560 N