2 Answers

Ishmael Smyrnow · Answer 1 · 2020-02-28T05:55:49+0000

The question is missing the figure. So, the figure is attached below.

Answer:

The area of the base of the pyramid is 36 square inches.

Explanation:

Given:

Volume of the pyramid is,
$V=108\ in^3$

The height of the pyramid is,
$h=9\ in$

Let the area of the base be 'A'.

So, the volume of the pyramid is given as:

V=(1)/(3)Ah

Rewrite the given formula in terms of 'A'. This gives,

A=(3V)/(h)

Now, plug in 108 for 'V', 9 for 'h' and solve for 'A'. This gives,

$A=(3* 108)/(9)\\\\A=3* 12\\\\A=36\ in^2$

Therefore, the area of the base of the pyramid is 36 square inches.

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