Question

A pi bond is formed by __________.

a. side-by-side overlap of two p orbitals
b. overlap of a p orbital with a f orbital
c. end-to-end overlap of two p orbitals
d. overlap of two d orbitals overlap of an s orbital with the end of a p orbital

Answer 1

A pi bond is created by the side-by-side overlap of two p orbitals, characterized by the electron density on opposite sides of the internuclear axis and a nodal plane where no electrons can be found. So the correct option is a.

Step-by-step explanation:

A pi bond (π bond) is a type of covalent bond that forms from the side-by-side overlap of two p orbitals. This side-by-side overlapping allows the electron density to be found on opposite sides of the internuclear axis, which is the line between the two nuclei where the bonding occurs. A pi bond is characterized by a nodal plane containing this internuclear axis, with no probability of finding an electron within that plane. This differentiates it from a sigma bond, which involves end-to-end overlap and has its electron density concentrated along the internuclear axis.

Answer 2

c. end-to-end overlap of two p orbitals

Step-by-step explanation:

A Pi bond is a covalent bond established by two atomic orbitals overlapping side-to-side. The combinations of these two atomic orbit may be px-px or py-py. A pi bond can be bonding or antibonding, identical to the sigma bonding.

hence the correct option for the question is c. end-to-end overlap of two p orbitals