Question

What is the value of x in the equation below?

1+2e^x+1=9
a). x=log4-1
b) x=log4
c). x=Ln4-1
d). x=ln4

Answer 1

C

Explanation:

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Answer 2

Answer: C

Explanation:

1+2e^x+1=9

2e^x+1=9-1

e^x+1= 8/2

e^x+1 = 4

Here we can applicate the Ln:

ln e^x+1 = ln 4

Applicating the log property for exponent:

(x+1).ln e = ln 4

Ln e = 1, so:

x+1 = ln 4

x = ln 4-1