Answer:
Therefore, Point M( 1 , -2 ) is the Mid point of segment ST.
Explanation:
Given:
Let,
point S( x₁ , y₁) ≡ ( -1 , 1)
point T( x₂ , y₂) ≡ (3 , -5)
Point M( x , y ) is the Mid point of segment ST.
To Find:
Point M( x , y )= ?
Solution:
As Point M( x , y ) is the Mid point of segment ST.
So we have Mid Point Formula as
![Mid\ pointM(x,y)=((x_(1)+x_(2) )/(2), (y_(1)+y_(2) )/(2))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ekzib5bke3o6aw4rc2yygor6lss8xd7n7a.png)
On substituting the given values in above equation we get
![M(x,y)=(\frac {-1+3}{2},(-5+1)/(2))\\\\M(x,y)=((2)/(2),(-4)/(2)) \\\\M(x,y)=(1,-2)\ \textrm{which the required midpoint}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6xnlnhni57llx43wrym5wo0mkmwu0e6yr5.png)
Therefore, Point M( 1 , -2 ) is the Mid point of segment ST.