Answer: 0.9738
Explanation:
We assume that the scores follows a normal distribution.
Let
denotes the class average .
As per given we have,

Sample size : n= 12
The probability that a class of 15 students will have a class average greater than 70 on Professor Elderman’s final exam will be :
![P(\overline{x}>70)=1-P(\overline{x}<70)\\\\=1-P(\frac{\overline{x}-\mu}{(\sigma)/(√(n))}<(70-76)/((12)/(√(15))))\\\\\approx1-P(z<-1.94)\ \ \ [\because\ z=\overline{x}-\mu}{(\sigma)/(√(n))}]\\\\ =1-(1-P(z<1.94))\ \ [\because P(Z<-z)=1-P(Z<z)]\\\\=1-1+P(z<1.94)\\\\=0+0.9738=0.9738\ \ \text{[By z-table]}](https://img.qammunity.org/2020/formulas/mathematics/college/ee1io6ggv2amkz66oyragux0iwi5ryf6ih.png)
Hence, the correct answer = 0.9738