Question

A collection of 33 coins having dimes quarters and nickels, there are 3 times more nickels then dimes and half the amount of dimes as nickels, all of the coins equal $3.30 how many of each coin?

Answer 1

Each coins are quarters of 6, nickels of 18 and the dimes of 9.

Explanation:

There is a mistake in question.

The question must be:

A collection of 33 coins having dimes quarters and nickels, there are 3 times as many nickels as quarters, and one-half as many dimes as nickels, all of the coins equal $3.30 how many coins of each kind are there?

Now, to find the number coins of each.

Let the quarters be
`x`.

Nickels be
`3x`.

And the dimes be
`(3x)/(2)`.

So, the total collection of coins are:

`x+3x+(3x)/(2) =33.`

On adding the fractions we get:

`(2x+6x+3x)/(2) =33`

`(11x)/(2) =33`

Multiplying both sides by 2 we get:

`11x=66`

Dividing both sides by 11 we get:

`x=6.`

Thus, quarters = 6.

Nickels =
`3x=3* 6=18.`

Dimes =
`(3x)/(2) =(3* 6)/(2) =(18)/(2)=9 .`

Therefore, each coins are quarters of 6, nickels of 18 and the dimes of 9.