Question

A publisher reports that 37% of their readers own a laptop. A marketing executive wants to test the claim that the percentage is actually different from the reported percentage. A random sample of 350 found that 30% of the readers owned a laptop. Make the decision to reject or fail to reject the null hypothesis at the 0.02 level.

Answer 1

0.1470

Explanation:

Hypothesis : H_0:=0.37 Vs H_1:
`\\eq[\tex] 0.30</p><p>The test statistic under H_o is given by ,</p><p>Z=[tex](p-p_0)/(√((p_0 q_0)/n))\rightarrow N(0,1)`

=
`(0.30-0.37)/(√(0.37*0.63/100))`

=
`(-0.07)/(√(0.00233))`

=-1.45

P value : P value = 2*P ( Z > | Z cal | )

= 2*P ( Z > 1.45 )

= 2*0.07352

= 0.14704