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The specific heat capacity of liquid water is 4.18 J/g-K.

How many joules of heat are needed to raise the temperature of 5.00 g of water from 25.1°C to 65.3°C?

2 Answers

3 votes

Final answer:

To raise the temperature of 5.00 g of water from 25.1°C to 65.3°C, 842.52 joules of heat are required, calculated using the water's specific heat capacity and change in temperature.

Step-by-step explanation:

The student asked how many joules of heat are needed to raise the temperature of 5.00 g of water from 25.1°C to 65.3°C. The specific heat capacity of liquid water is given as 4.18 J/g°C. To calculate the heat (q) required, we use the formula q = mass × specific heat capacity × ΔT, where ΔT is the change in temperature.

ΔT = final temperature - initial temperature
ΔT = 65.3°C - 25.1°C
ΔT = 40.2°C

Now, let's calculate the heat required:

q = 5.00 g × 4.18 J/g°C × 40.2°C
q = 842.52 J

Therefore, 842.52 joules of heat are needed to raise the temperature of 5.00 g of water from 25.1°C to 65.3°C.

User Sebastian Siek
by
4.6k points
2 votes

Answer:

840.18

Step-by-step explanation:

Use the equation: Q = mcΔT

m = mass (5 g)

c = specific heat (4.18)

ΔT = change in temperature (65.3-25.1 = 40.2)


5*4.18*40.2 = 840.12

User Gwyn
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5.8k points