Answer:
length of rectangle=6cm
width of rectangle=11cm
Explanation:
let, width of rectangle=x
length of rectangle=x-5
area of rectangle=
![length*(width)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xs3nq0axo0np0u3te1weueq0u78vm28xbx.png)
given area of rectangle=66
so 66=
![x*(x-5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/seuidjalaebvwyc0ldcl8kbz7wqc5g2lqq.png)
66=x^2-5x
x^2-11x+6x-66=0
x(x-11)+6(x-11)=0
(x+6)(x-11)=0
x=-6,11
here x=11 is acceptable
length of rectangle=x-5=11-5=6cm
length of rectangle=6cm
width of rectangle=11cm answer