Question

Blood flows through a section of a horizontal artery that is partially blocked by a deposit along the artery wall. As a hemoglobin molecule moves from the narrow region into the wider region, its speed changes from v2 = 0.800 m/s to v1 = 0.630 m/s. What is the change in pressure, P1 - P2, that it experiences? The density of blood is 1060 kg/m3.

Answer 1

`\Delta P=128.843\ Pa`

Step-by-step explanation:

given,

speed of blood = v₂ = 0.800 m/s

v₁ = 0.630 m/s

density of blood = 1060 kg/m³

Atmospheric pressure = 8.89 ✕ 10⁴ N/m²

Using Bernoulli equation

`P_1 - P_2 = (1)/(2)\rho (v_2^2-v_1^2)`

`\Delta P= (1)/(2)\rho (0.8^2-0.63^2)`

`\Delta P= (1)/(2)* 1060* (0.8^2-0.63^2)`

`\Delta P=128.843\ Pa`

the change of pressure is equal to
`\Delta P=128.843\ Pa`