Question

Find the roots of the quadratic equation :


`x ^(2) + x + 2 = 0`
No copied ans no spams​

Answer 1

Explanation:

x = (-b ± √ (b² - 4ac) )/2a.

Answer 2

• 
  `\sf {x}^(2) + x + 2 = 0`

• 
  `\sf{x}^(2) - 2x + x - 2 = 0`

• 
  `\sf \: x(x + 2) - 1(x + 2) = 0`

• 
  `\sf \: (x - 1)(x + 2) = 0`

• 
  `\sf \: x - 1 = 0 \: \: \: \: \: \: \: \: \: x + 2 = 0`

• 
  `\boxed{ \sf \: x = 1 \: \: \: \: \: \: x = - 2}`

`\sf{ \large \underline {Hope \: \: It's \: \: Welps \: \: uhh}}`