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The vertex of y=x^2+12x+32
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The vertex of y=x^2+12x+32

User Jordan Jambazov
by
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1 Answer

9 votes

Answer:

The vertex is y=-4

Explanation:

The vertex is the minimum point of the graph of the quadratic equation.

Let's first find the like of symmetry.

dy/dx=2x+12

2x+12=0

2x=-12

x=-6

Now plug -6 into the quadratic equation

y=(-6)²+12(-6)+32

y=-4

User Jgibson
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