Question

A vertical spring has a spring constant of 100 newtons per meter. When an object is attached to the bottom of the spring, the spring changes from its unstretched length of 0.50 meters to a length of 0.65 meters. The magnitude of the weight of the attached object is

a. 1.1N
b. 15N
c. 50N
d. 65N

Answer 1

option B

Step-by-step explanation:

given,

spring constant = k = 100 N/m

distance of unstretched length = 0.5 m

distance after stretched length = 0.65 m

magnitude of weight = ?

We know,

W = K x

x is the displacement

x = 0.65 - 0.5 = 0.15 m

W = K x

W = 100 x 0.15

W = 15 N

Hence, the correct answer is option B