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A centrifuge is a common laboratory instrument that separates components of differing densities in solution. This is accomplished by spinning a sample around in a circle with a large angular speed. Suppose that after a centrifuge in a medical laboratory is turned off, it continues to rotate with a constant angular deceleration for 10.0s before coming to rest.

Part A

If its initial angular speed was 3890rpm , what is the magnitude of its angular deceleration? (|?| in revs/s^2 )

Part B

How many revolutions did the centrifuge complete after being turned off?

User Ive
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1 Answer

4 votes

Answer:


a_r=389\ rev.s^(-2)


n=58350 rev

Step-by-step explanation:

Given:

time of constant deceleration,
t=10\ s

A.

initial angular speed,
N_i=3890\ rpm\

Using equation of motion:


N_f=N_i+a_r.t


0=3890+a_r* 10


a_r=389\ rev.s^(-2)

B.

Using eq. of motion for no. of revolutions, we have:


n=N_i.t+(1)/(2) a_r.t^2


n=3890* 10+0.5* 389* 100


n=58350\ rev

User Adrian Seeley
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