Question

Pure acetic acid has a density of 1.049g / (ml) . Calculate the molarity of a solution of acetic acid made by dissolving 20.00 ml in enough water to make 250.0 ml of solution

Answer 1

Molarity = 1.4 M

Step-by-step explanation:

Given data:

Density of acetic acid = 1.049 g/mL

Volume of acetic acid = 20.0 mL

Volume of solution = 250.0 mL (250/1000 = 0.25 L)

Molarity = ?

Solution:

Mass of acetic acid = density × volume

Mass of acetic acid = 1.049 g/mL × 20.0 mL

Mass of acetic acid = 20.98 g

Number of moles of acetic acid = mass/ molar mass

Number of moles of acetic acid = 20.98 g/ 60.052 g/mol

Number of moles of acetic acid = 0.35 mol

Molarity = number of moles / volume in L

Molarity = 0.35 mol / 0.25 L

Molarity = 1.4 M