Answer: The Answer is 2x^2+8x+22+90/x-4 or in other words, D.
Explanation:
First you have to find out how many x^3, X^2, and x's you have.
In this case, we have 2 x^3, we have 0 x^2' s and -10 x's, now to find your remainder and final answer, we have to use synthetic division.
Place your numbers like so:
2 0 -10 +2 (What is on the top gets added and whats on the bottom gets multiplied by 4, our divisor)
2 0 -10 +2
-----+8---32-----------
2(4) 8(4) 22(4) =88+2=90 (your remainder)
Notice how our final answer is already lined up for us (2, 8, 22, 90)
Now, before we submit our final answer, we have to once again look back at our original equation. We began the equation with 2x^3, but to write our final answer we need to use an exponent less than 2x^3, therefore, your final answer will be
2x^2+8x+22+90/x-4 (only your remainder goes over your devisor 90/x-4)