Answer:
Yes, the distance from
is 4 units
Explanation:
step 1
Find the radius of the circle
we know that
The distance between the center and any point that lie on the circle is equal to the radius of the circle
In this problem we have
the center is (-2,0)
Find the distance between (-2,0) and (-2,4)
the formula to calculate the distance between two points is equal to
![d=\sqrt{(y2-y1)^(2)+(x2-x1)^(2)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/cludwa9rlbp5l9xccb2d39dpew3fngh0ii.png)
substitute
![r=\sqrt{(4-0)^(2)+(-2+2)^(2)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/f4rkxcpugjjfiqclugqa241mx2ttm9rat6.png)
![r=\sqrt{(4)^(2)+(0)^(2)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/c35tj7q0r0h1cy5ug4jmappeb6doqxhhpc.png)
![r=4\ units](https://img.qammunity.org/2020/formulas/mathematics/high-school/4tg0kf7xwr00c9qgbspecp4nt13l6q02ov.png)
step 2
Verify if the point
lie on the circle
Find the distance between the center and the given point and compare the result with the value of the radius
we have
![(-2,0),(1,√(7))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mhucw3dkagdm5ngndwpribhrf0wn42qfl5.png)
substitute in the formula
![d=\sqrt{(√(7)-0)^(2)+(1+2)^(2)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/i9pojcgj9rnrnp628zr48o2wfgvmoz0dqt.png)
![d=\sqrt{(√(7))^(2)+(3)^(2)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/iynm42q0vj0e75fy8aqrf4rmetalwz143b.png)
![d=√(16)](https://img.qammunity.org/2020/formulas/mathematics/high-school/b3mpwth08le6zh78f7nqilquaul8f998h1.png)
![d=4\ units](https://img.qammunity.org/2020/formulas/mathematics/middle-school/uoelyji7ik6qgw6w7u2gfb5rcubaj36ea6.png)
The distance is equal to the radius
therefore
The point
lie on the circle