Question

HI. Can you help???

The table shows the total distance a spider traveled after a light was turned on.

Between which two consecutive times was the average rate of change the greatest?
Question 3 options:

A. between Second 11 and Second 15

B.between Second 19 and Second 28

C. between Second 5 and Second 11

D.between Second 15 and Second 19

Answer 1

The maximum rate of change is between second 15 and second 19.

Explanation:

See the attached table.

The table shows the total distance a spider traveled after a light was turned on.

Now, the average rate of change between two consecutive times in the table is given by

=
`\frac{\textrm {Total change in Distance in feet}}{\textrm {Total change in Time in seconds }}`

Therefore, between second 5 and second 11, the average rate of change =
`(7 - 4)/(11 - 5) = 0.5`

Between second 11 and second 15, the average rate of change =
`(13 - 7)/(15 - 11) = 1.5`

Between second 15 and second 19, the average rate of change =
`(20 - 13)/(19 - 15) = 1.75`

Between second 19 and second 28, the average rate of change =
`(24 - 20)/(28 - 19) = 0.44`

Therefore, the maximum rate of change is between second 15 and second 19. (Answer)