Question

Monochromatic light (light of a single wavelength) is to be absorbed by a sheet of photographic film and thus recorded on the film. Photon absorption will occur if the photon energy equals or exceeds 0.6eV, the smallest amount of energy needed to dissociate an AgBr molecule in the film. What is the greatest wavelength of light that can be recorded by the film?

Answer 1

Answer:
`2.07* 10^(-6) m`

Step-by-step explanation:

Given

Photon absorption will occur at an Energy level of
`0.6 eV\approx 0.96* 10^(-19) J`

and Energy is given by

`E=(hc)/(\lambda )`

where h=Planck constant

c=velocity of light

`\lambda =`Wavelength

`E_(min)=(hc)/(\lambda _(max))`

`\lambda _(max)=(19.878* 10^(-26))/(0.96* 10^(-19))`

`\lambda _(max)=2.07* 10^(-6) m`