Answer:
The speed at which water will initially flow out of the hole is 12.5 m/s.
Step-by-step explanation:
It is given that,
The water level in the container, h = 20 cm
Height of the hole above ground, h' = 12 cm
We need to find the speed at which water will initially flow out of the hole. It can be calculated using the conservation of energy. It is given by equation the kinetic energy gained and the potential energy lost.
![v=√(2gH)](https://img.qammunity.org/2020/formulas/physics/college/poecshpd1veeu6brcxmj2h8sbwum3jxwiu.png)
H = h - h'
H = 20 cm - 12 cm = 8 cm
![v=√(2* 9.8\ m/s^2* 8\ m)](https://img.qammunity.org/2020/formulas/physics/college/g1ss0nvujzojhc0ih0un1pxecymko135hq.png)
v = 12.52 m/s
or
v = 12.5 m/s
So, the speed at which water will initially flow out of the hole is 12.5 m/s. Hence, this is the required solution.