Answer:
![(1)/(6561)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wrxxs8r6vquutzl5hsagzct54l9qyuak97.png)
Explanation:
This is a "power" raised to another "power" problem. Lets see the rule of exponents that dictates solving this type of problem.
Power rule of Exponents:
![(a^b)^c=a^(bc)](https://img.qammunity.org/2020/formulas/mathematics/high-school/8l0dpzguk924bwhcrjrz9djm4oq8apr76o.png)
We basically multiply the powers together. So this problem becomes:
![[3^(-2)]^4=3^(-2*4)=3^(-8)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/753nrrp5sgluuyfb5jrp9acbfgl7h2hdou.png)
We can use another property to make it simpler. The property is:
![a^(-b)=(1)/(a^b)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6r6ga8m212rk2stied0jzvcyrgfzq70ovz.png)
So, the problem becomes:
![(1)/(3^8)=(1)/(6561)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kmsmgbqo3dpabhdf614vwvwqltyvf5hs9i.png)
In fractional form, this is the answer:
![(1)/(6561)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wrxxs8r6vquutzl5hsagzct54l9qyuak97.png)