Answer:
The expected value is 1.8
Explanation:
Consider the provided information.
Suppose there’s a 15% chance of having 0 announcements, a 30% chance of having 1 announcement, a 25% chance of having 2 announcements, a 20% chance of having 3 announcements, and a 10% chance of having 4 announcements.
![\text{Expected Value}=a \cdot P(a) + b \cdot P(b) + c \cdot P(c) + \cdot\cdot](https://img.qammunity.org/2020/formulas/mathematics/college/e5fqw9h4jun9hlzhnb509p9ts81ddflhxs.png)
Where a is the announcements and P(a) is the probability.
![\text{Expected Value}=0\cdot 15\% + 1 \cdot 30\% + 2 \cdot 25\% + 3\cdot20\%+4\cdot10](https://img.qammunity.org/2020/formulas/mathematics/college/yd5hobbx2pb0hv4jd8kjdyerrrullzqpz1.png)
![\text{Expected Value}=1 \cdot 0.30+2 \cdot 0.25 +3 \cdot 0.2 + 4\cdot 0.10](https://img.qammunity.org/2020/formulas/mathematics/college/wtvjhiz8r5s239t2mmq0y9ilu746i4jfu8.png)
![\text{Expected Value}=1.8](https://img.qammunity.org/2020/formulas/mathematics/college/skpzchf9z6euiba1c8vyu055dnn36mq9b5.png)
Hence, the expected value is 1.8