Question

An astronaut drops a ball off the edge of a crater on the Moon, where gravity is 1.6 m/s(s). If it takes 5 seconds for the ball to reach the bottom of the crater, what is the depth of the crater? (Need HELP, AAAAAAAAAAAAAAAAAAAAAA.)

Answer 1

The depth of the crater is 20[m]

Step-by-step explanation:

We can solve this problem using the kinematics equations, it should be noted that the negative sign of acceleration means that the drop of the object is down.

Data:

a = 1.6[m/s^2]

t = 5 [s]

`y=y_(0) +v_(0) *t-(1)/(2) *g*(t)^(2)`

v0= 0, because there is not initial veocity

y = final distance = 0 the bottom of the crater

g = a = acceleration of the crater [m/s^2]

y0= Point where the ball was dropped. = Distance from the original point to the bottom of the crater.

`y_(0) =(1)/(2)*1.6*(5)^(2)\\  y_(0) = 20 [m]`