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2 votes
If five joules were required to move a crate in 3.7 seconds, what power was applied?

User Weisk
by
5.8k points

1 Answer

3 votes

Answer:

The answer to your question is 1.35 Watts

Step-by-step explanation:

Data

Work = W = 5 J

time = t = 3.7 s

Power = P = ?

Formula

Power is a rate in which work is done or energy is transferred over time

P =
(W)/(t)

Substitution


P = (5)/(3.7)

Result

P = 1.35 W

User Esterlin
by
6.1k points