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Starting from rest, Christina experiences 24.5 m/s2 of acceleration to take off from an aircraft carrier for 5 seconds. How long does the runway need to be? Round to the nearest meter.

User Adharris
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1 Answer

2 votes

Answer:

The length of the runway to the nearest meter is 306 m.

Step-by-step explanation:

Given:

Initial velocity of Christina is,
u=0\ m/s(Rest)

Time taken is,
t=5\ s

Acceleration experienced by Christina is,
a=24.5\ m/s^2

The length of the runway is,
d=?

Now, we use Newton's equation of motion that relates the distance, initial velocity, time and acceleration.

So, we have the following equation of motion:


d=ut+(1)/(2)at^2

Plug in all the given values and solve for 'd'. This gives,


d=0+(1)/(2)* 24.5* 5^2\\\\d=(1* 24.5* 25)/(2)\\\\d=(612.5)/(2)\\\\d=306.25\approx 306\ m(\textrm{Rounding to nearest meter})

Therefore, the length of the runway to the nearest meter is 306 m.

User Ekj
by
8.3k points
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