Answer:
The length of the runway to the nearest meter is 306 m.
Step-by-step explanation:
Given:
Initial velocity of Christina is,
![u=0\ m/s(Rest)](https://img.qammunity.org/2020/formulas/physics/middle-school/t49udbzanaybwv5swrydrl6pc9wn8hv76o.png)
Time taken is,
![t=5\ s](https://img.qammunity.org/2020/formulas/physics/middle-school/c55jtwm6rv5f7n37ewgkld0kv4purxt7w2.png)
Acceleration experienced by Christina is,
![a=24.5\ m/s^2](https://img.qammunity.org/2020/formulas/physics/middle-school/82t6dk07jcgwh40re865jnc4ttq39u6nq5.png)
The length of the runway is,
![d=?](https://img.qammunity.org/2020/formulas/physics/middle-school/hrmd2vhsnltx7uedzvzh9cfzd9t010dmho.png)
Now, we use Newton's equation of motion that relates the distance, initial velocity, time and acceleration.
So, we have the following equation of motion:
![d=ut+(1)/(2)at^2](https://img.qammunity.org/2020/formulas/physics/high-school/495jj12aijffa7t0ry8ikukju3rvqwk8ni.png)
Plug in all the given values and solve for 'd'. This gives,
![d=0+(1)/(2)* 24.5* 5^2\\\\d=(1* 24.5* 25)/(2)\\\\d=(612.5)/(2)\\\\d=306.25\approx 306\ m(\textrm{Rounding to nearest meter})](https://img.qammunity.org/2020/formulas/physics/middle-school/bq8msdyyckzwrtbeyoxdraeumfc6ppu69r.png)
Therefore, the length of the runway to the nearest meter is 306 m.