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In a study of automobile collision insurance costs, a random sample of n = 35 repair costs of front-end damage caused by hitting a wall at a specified speed had a mean of $1,438. (a) Given that σ = $269 for such data, what can be said with 98% confidence about the maximum error if x = $1, 438 is used as an estimate of the average cost of such repairs.

User Tom Dufall
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Answer: The maximum error = $105.76.

Explanation:

Formula to find the maximum error:


E= z^*(\sigma)/(√(n))

, where n= sample size.


\sigma = Population standard deviation

z*= Critical value(two-tailed).

As per given , we have


\overline{x}=1438

n= 35


\sigma=269

For 98% confidence , the significance level =
1-0.98=0.02

By z-table , the critical value (two -tailed) =
z^* = z_(\alpha/2)=z_(0.01)=2.326

Now , the maximum error =
E= (2.326)(269)/(√(35))


E= (2.326)(269)/(5.9160797831)


E= (2.326)*45.4692989044=105.761589252\pprox105.76

Hence, With 98% confidence level , the maximum error = $105.76.

User Akshaynagpal
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