Answer:
$289.41
Explanation:
As we know that the total amount 'A' that is due to pay on loan for a certain interest 'r', principal 'p' and number of times the interest is compounded per year 'n' is:
![A = p (1+(r)/(n))^(nt)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/grttdqedc5vus77741190m3b6tqdrud4ix.png)
Since, in our case, p = $43,000, r = 2.4% =
= 0.024, n = 12 (monthly), and t = 20 years.
Therefore,
![A = 43000 (1+(0.024)/(12))^((12)(20))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/s4izjr9rz7upxi772fjg68fqjlgqndxgee.png)
$
For monthly payment for 20 years,
![A = (69457.89)/((12)(20))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3boxjmp9qccghv6nbdg8oq5381nrd964h6.png)
$ ≈ $289.41
Hence, the amount of his monthly payment lasting for 20 years at APR of 2.4% on a loan of $43,000 compounded monthly will be $289.41.