Question

6. You are in an airplane going down a runway currently going 24 m/s and accelerating at 8 m/s?

for 800 m until takeoff. How long does it take the plane to go those 800 m?

Answer 1

The time taken by the airplane to take off, t = 11.46 s

Step-by-step explanation:

Given data,

The initial velocity of the airplane, u = 24 m/s

The acceleration of the plane, a = 8 m/s

The distance covered until take off, d = 800 m

Using the III equation of motion,

v² = u² +2as

= 24² + 2 x 8 x 800

= 13376

v = 115.65 m/s

Using the first equation of motion,

v = u + at

t = (v-u) / a

= (115.65 - 24) / 8

= 11.46 s

Hence, the time taken by the airplane to take off, t = 11.46 s