Initial velocity of the object = 31.4 m/s
Step-by-step explanation:
If an object is thrown downward with an initial velocity of v₀, then the distance it travels is given by s = 4.9 t²+v₀t
Now an object is thrown downward from a cliff 400 m high and it travels 138.3 m in 3 sec. We need to find initial velocity of the object.
s = 4.9 t²+v₀t
138.3 = 4.9 x 3²+ v₀ x 3
3v₀ = 94.2
v₀ = 31.4 m/s
Initial velocity of the object = 31.4 m/s