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2 votes
What equation is perpendicular to y=2x-3 and
passes through (-1, 2)?

User FrostyFire
by
8.2k points

1 Answer

4 votes

Answer:


\[y=-(1)/(2)x+(5)/(2)\]

Explanation:

Equation of the given line:
\[y=2x-3\]

Slope of the line =
\[2\]

Slope of the perpendicular line =
\[-(1)/(2)\]

So the equation of the perpendicular line:


\[y=-(1)/(2)x+c\]

This passes through the point (-1,2).Substituting in the equation:


\[2=-(1)/(2)*(-1)+c\]

=>
\[c=2+(1)/(2)\]

=>
\[c=(5)/(2)\]

So the equation of the line :


\[y=-(1)/(2)x+(5)/(2)\]

User David Brochart
by
7.8k points

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