Question

I drop an egg from a certain distance and it takes the egg 3.74 seconds to reach the ground. How high up was the egg?

Answer 1

The height from which the egg is dropped is 68.54 m.

Step-by-step explanation:

Given:

Initial velocity of egg is,
`u=0\ m/s`(Dropped means initial velocity is 0)

Time taken is,
`t=3.74\ s`

Acceleration experienced by egg is due to gravity,
`a=g=9.8\ m/s^2`

The height from which the egg is dropped is,
`d=?`

Now, we use Newton's equation of motion that relates the distance, initial velocity, time and acceleration.

So, we have the following equation of motion:

`d=ut+(1)/(2)at^2`

Plug in all the given values and solve for 'd'. This gives,

`d=0+(1)/(2)* 9.8* (3.74)^2\\\\d=(1* 9.8* 13.9876)/(2)\\\\d=(137.078)/(2)\\\\d=68.54\ m`

Therefore, the height from which the egg is dropped is 68.54 m.