193k views
0 votes
April sold 75 tickets to the school Christmas play and collected $495. If adult tickets cost $8 and children tickets were $5 how many adult and children tickets were sold

User Egiray
by
5.2k points

2 Answers

2 votes
The adults would be 40 bucks and the kids would be 35 you are welcome u goons
User CharlieB
by
5.5k points
3 votes

Answer:

Explanation:

~First we have to write our two equations that are:

1. 8x+5y=$495(becoz the no. of adult tickets is unknown and children is unknown we use variables instead and multiplying them with the amount of money for each gives us 495)

2. x+y=75( No. of adult tickets and children altogether gives us 75)

~Use the substitution method by using any of the equations and putting the variable you want as the subject and then putting its values in the next equation:

x+y=75

x=75-y

~Substitute to find y(no. of children’s ticket)

8x+5y=495

8(75-y)+5y=495

600-8y+5y=495

-8y+5y=495-600

-3y=-105

y=-105/-3

y=35

Therefore, the no. of children tickets is 35.

~Substituting y in the substitution equation(x=75-y):

x=75-35

x=40

Therefor no. of tickets sold to adults is 40.

~Final answers:

Adults=40

Children=35

User Nnog
by
5.6k points