Question

Can someone solve this molarity problem? i’m stuck on it.

Answer 1

The molarity of the solution is 1.854 mol/L

Step-by-step explanation:

The weight of
`Na_(2)C_(2)O_(4)` present in 131.64mL of 2.7 M solution:

`Molarity=(no.\:of\:moles)/(Volume\:of\:solution\:in\:L)\\Molarity\:of\:the\:solution=2.7M\\Volume\:of\:solution=131.64ml=0.13164L\\No.\:of\:moles=0.355428\\Weight\:of\:Na_(2)C_(2)O_(4)=43.36g\\To\:this\:solution\:14.13g\:of\:Na_(2)C_(2)O_(4)\:is\:added.\\Total\:weight\:of\:Na_(2)C_(2)O_(4)=57.49g\\No.\:of\:moles=0.471\\Final\:Volume\:of\:Solution=254.18mL=0.25418L\\Molarity\:of\:the\:final\:solution=(0.471)/(0.25418)=1.854\:mol/L`

Hence, the molarity of the solution is 1.854 mol/L