Answer:
The distance in meters traveled by the drag racer in 6 seconds is 180.
Step-by-step explanation:
Given:
A drag racer starts from rest. So, initial velocity of the drag racer,
![v_i=0](https://img.qammunity.org/2020/formulas/physics/high-school/f0qytlszd8xxbfktjduunfo8wa6zpv6fgg.png)
Time taken is,
![t=6\ s](https://img.qammunity.org/2020/formulas/physics/middle-school/8eipzsrn0fgygqt842399zu5nif1y5r7cs.png)
Acceleration of the drag racer is,
![a=10\ m/s^2](https://img.qammunity.org/2020/formulas/physics/college/fwn9t3zmej2tptrxhgc0pbb25mwax2g9v9.png)
Now, we are asked to find how far will he reach in 6 seconds. So, we are asked the displacement, 'd'.
We use the following kinematic equation to find 'd'.
![d=v_it+(1)/(2)at^2](https://img.qammunity.org/2020/formulas/physics/college/nnrx8mwwqiy7ao53t1g7xy4hqo63zssjaq.png)
Plug in the given values and solve for 'd'. This gives,
![d=0+(1)/(2)(10)(6)^2\\d=5* 36\\d=180\ m](https://img.qammunity.org/2020/formulas/physics/middle-school/e1o1kep86hrfew5uiixxulkv3wo8ksge54.png)
Therefore, the distance in meters traveled by the drag racer in 6 seconds is 180.