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A drag racer starts from rest and

accelerates at 10 m/s2. How far will he
travel in 6 seconds? Use the appropriate
Kinematic equation(s) given to determine
the answer.
ROUND TO ONE DECIMAL PLACE, DO
NOT INCLUDE UNITS IN YOUR
ANSWER!!!

1 Answer

5 votes

Answer:

The distance in meters traveled by the drag racer in 6 seconds is 180.

Step-by-step explanation:

Given:

A drag racer starts from rest. So, initial velocity of the drag racer,
v_i=0

Time taken is,
t=6\ s

Acceleration of the drag racer is,
a=10\ m/s^2

Now, we are asked to find how far will he reach in 6 seconds. So, we are asked the displacement, 'd'.

We use the following kinematic equation to find 'd'.


d=v_it+(1)/(2)at^2

Plug in the given values and solve for 'd'. This gives,


d=0+(1)/(2)(10)(6)^2\\d=5* 36\\d=180\ m

Therefore, the distance in meters traveled by the drag racer in 6 seconds is 180.

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