Question

Find two numbers whose difference is three when the larger number is decreased by three times the smaller number the result is -11

Answer 1

The two numbers are 10 and 7.

Explanation:

Given:

The two numbers whose difference is three, when the larger number is decreased by three times the smaller number the result is -11.

Now, find the two numbers.

Let the larger number be
`x`.

Let the smaller number be
`y`.

As given, the two numbers whose difference is three:

`x-y=3`

`x=3+y`

So, the value of
`x=3+y`.

According to question:

`x-3y=-11`

Putting the value of
`x` we get:

`3+y-3y=-11`

`3-2y=-11`

Moving variables on one side and the number on the other we get:

`3+11=2y`

`14=2y`

Dividing both sides by 2 we get:

`7=y`

The smaller number = 7.

Now, putting the value of
`y` in the equation
`x-y=3`:

`x-y=3`

`x-7=3`

Adding both sides by 7 we get:

`x=10.`

The larger number = 10.

Therefore, the two numbers are 10 and 7.