Answer:
E
Step-by-step explanation:
The parallel plate capacitor is being charged by a steady current i. If the constant current is flowing along a straight wire, what happens inside the capacitor, between the plates is that the induced magnetic field strength is zero Tesla near the center of the plates and increases as r increases toward the edges of the plates.
From Ampère–Maxwell law, the magnetic field between the capacitor plates assuming that the capacitor is being charged at a constant rate by a steady current is
B = μ₀r /2A
where;
μ₀ is permeability
Q(t) is the instantaneous charge on the positive plate,
A is the cross-sectional area of a plate and
e₀ is a unit vector