Answer:
The correct option is e)
![H_0: \mu_1=\mu_2\ and\ H_a:\mu_1\\eq \mu_2](https://img.qammunity.org/2020/formulas/mathematics/college/33yg41nckdfwqr5e8dw2s7h81fcpy052nz.png)
Explanation:
Consider the provided information.
Ten college students reported that they consume coffee but do not smoke cigarettes; these comprise the Coffee-Only group, or Group 1. Another ten college students reported that they consumed coffee and also smoked cigarettes; these comprise the Coffee + Cigarettes group, or Group 2.
The null hypothesis tells the population parameter is equal to the claimed value.
If there is no statistical significance in the test then it is know as the null which is denoted by
, otherwise it is known as alternative hypothesis which denoted by
.
The amount of coffee that "coffee drinkers" consume on a weekly basis differs depending on whether the coffee drinker also smokes cigarettes.
Thus, the required hypothesis are:
![H_0: \mu_1=\mu_2\ and\ H_a:\mu_1\\eq \mu_2](https://img.qammunity.org/2020/formulas/mathematics/college/33yg41nckdfwqr5e8dw2s7h81fcpy052nz.png)
Therefore, the correct option is e)
![H_0: \mu_1=\mu_2\ and\ H_a:\mu_1\\eq \mu_2](https://img.qammunity.org/2020/formulas/mathematics/college/33yg41nckdfwqr5e8dw2s7h81fcpy052nz.png)