Question

A photon has momentum of magnitude 8.30×10−28 kg⋅m/s . Part APart complete What is the energy of this photon? Give your answer in joules. E = 2.49×10−19 J SubmitPrevious Answers Correct Part BPart complete What is the energy of this photon? Give your answer in electron volts. E = 1.55 eV SubmitPrevious Answers Correct Part C What is the wavelength of this photon?

Answer 1

Answer with Explanation:

We are given that

Momentum of photon=
`8.3* 10^(-28) kg.m/s`

a. We have to find the energy of this photon.

Speed of photon=
`c=3* 10^8 m/s`

We know that

Momentum=p=
`(h)/(\lambda)`

Where

h=
`6.63* 10^(-34)`J-s=Plank's constant

`\lambda=`Wavelength of photon

`\lambda=(h)/(p)`

`\lambda=(6.63* 10^(-34))/(8.3* 10^(-28))`

`\lambda=7.99* 10^(-7)` m

`E=(hc)/(\lambda)`

`E=(6.63* 10^(-34)* 3* 10^8)/(7.99* 10^(-7))`

`E=2.49* 10^(-19)` J

Hence, the energy of photon=
`2.49* 10^(-19)` J

B.Energy of photon in electron volt=
`(2.49* 10^(-19))/(1.6* 10^(-19))=1.55 eV`

Energy of photon=
`1.55eV`

C.Wavelength of photon =
`\lambda=7.99* 10^(-7)m`