Answer:
On that day 1500 children and 700 adults attended.
Explanation:
Given:
There is a carnival. Children are $1.50 and adults are $4.
The total amount of money raised was $5050.
On this particular day there 2200 in attendance.
Now, to find the children and adults attended on that day.
Let the children attended be
.
And the adults attended be
.
The total number in attendance:
![x+y=2200](https://img.qammunity.org/2020/formulas/mathematics/middle-school/krw18rkqfcfqrpvnuy9k75xd3a4hat04yz.png)
⇒
........( 1 ).
Now, the total amount of money raised:
![1.50x+4y=5050](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6rjlufrihyeo9brxncvmdr0huw81iwv9mh.png)
Putting the equation ( 1 ) in the place of
we get:
⇒
![1.50(2200-y)+4y=5050](https://img.qammunity.org/2020/formulas/mathematics/middle-school/akcbqfm4236jrohnye12ar8453xtdias2m.png)
⇒
![3300-1.50y+4y=5050](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8a989w7e57wz1tc0ehnblmvafkhq2qjul1.png)
⇒
Subtracting both sides by 3300 we get:
⇒
![2.50y=1750](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2srt27pjcz7esxn9725e6kldplpk4ulcs4.png)
Dividing both sides by 2.50 we get:
⇒
![y=700.](https://img.qammunity.org/2020/formulas/mathematics/middle-school/yhuj9u49s4fvu9f1u8kgmtk7f0q2f06ewu.png)
The adults attended = 700.
Now, putting the value of
in equation ( 1 ) we get:
![x=2200-700](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gyaz158wn77mr0ntmh9hs5c16iqtx0588v.png)
⇒
![x=1500.](https://img.qammunity.org/2020/formulas/mathematics/middle-school/54hgyt2u8pwzhruth891rrh639g3lazmox.png)
The children attended = 1500.
Therefore, on that day 1500 children and 700 adults attended.