Answer:
The system is at equilibrium
Step-by-step explanation:
Let's consider the following reversible reaction.
2 SO₂(g) + O₂(g) ⇄ 2 SO₃(g)
To determine whether a reaction is at equilibrium or not, we have to calculate the reaction quotient (Q).
![Q=([SO_(3)]^(2))/([SO_(2)]^(2).[O_(2)]) =((9.00)^(2) )/((6.00)^(2)* 0.45) =5.0](https://img.qammunity.org/2020/formulas/chemistry/college/qwieikzt6xyoirozgp8097hnj9uzoms0r8.png)
Since Q = K (equilibrium constant), regardless of the significant figures, the system is at equilibrium.