Question

radio signals travel at a rate of 3 x 10^8 meters per second. how many seconds will it take for a radio signal to travel from a satellite to the surface of earth if the satellite is orbiting at a height of 3.6 x10^7 meters? Write the answer in scientific notation.

Answer 1

`time=1.2* 10^(-1)\ second`

Explanation:

Given:

The speed of the radio is
`3* 10^(8)` meters per second.

The distance of the satellite from the earth is
`3.6* 10^(7)` meter

The formula of the speed is

`speed = (distance)/(time)`

For time the formula is.

`time = (distance)/(speed)`

put distance and speed value in above equation.

`time = (3.6* 10^(7))/(3* 10^(8))`

`time = (1.2 x 10^(7))/(10^(8))`

`time=1.2* 10^(7)* 10^(-8)`

`time=1.2* 10^(7-8)`

`time=1.2* 10^(-1)\ second`

Therefore, the radio will be take the time is
`1.2* 10^(-1)\ second` or 0.12 seconds.