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What is the axis of symmetry of the parabola y= 1/3 (x-10)^2 - 6

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Answer:

The equation of the axis of symmetry is equal to


x=10

Explanation:

we have


y=(1)/(3)(x-10)^2-6

This is the equation of a vertical parabola written in vertex form open upward (because the leading coefficient is positive)

The vertex represent a minimum

The axis of symmetry is equal to the x-coordinate of the vertex

we have that

The vertex is the point (10,-6)

The x-coordinate of the vertex is 10

therefore

The equation of the axis of symmetry is equal to


x=10

User Ahmet Karakaya
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