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How can I solve this question

How can I solve this question-example-1

1 Answer

4 votes

Answer:

The value of x can be 5 or 2

Explanation:

In given triangle ABC

Interior Angle A =
x^(2) +3x+20

Interior Angle B =
x^(2) +14x-5

Exterior Angle I =
3x^(2) +10x+25

We know that

Exterior Angle of triangle is summation of corresponding opposite angles

Angle I = Angle A + Angle B


3x^(2) +10x+25= (x^(2) +3x+20)+(x^(2) +14x-5)


3x^(2) +10x+25= 2x^(2) +17x+15


1x^(2)-7x+10=0


x^(2)-2x-5x+10=0


x(x-2)-5(x-2)=0


(x-5)(x-2)=0

User Xorsyst
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