Question

How can I solve this question

Answer 1

The value of x can be 5 or 2

Explanation:

In given triangle ABC

Interior Angle A =
`x^(2) +3x+20`

Interior Angle B =
`x^(2) +14x-5`

Exterior Angle I =
`3x^(2) +10x+25`

We know that

Exterior Angle of triangle is summation of corresponding opposite angles

Angle I = Angle A + Angle B

`3x^(2) +10x+25= (x^(2) +3x+20)+(x^(2) +14x-5)`

`3x^(2) +10x+25= 2x^(2) +17x+15`

`1x^(2)-7x+10=0`

`x^(2)-2x-5x+10=0`

`x(x-2)-5(x-2)=0`

`(x-5)(x-2)=0`