Question

A sound is recorded at 19 decibels. What is the intensity of the sound?

Answer 1

The intensity of the sound will be 7.94 × 10^-11 W/m^2 .

Step-by-step explanation:

Decibels = dB = 19

The formula to calculate intensity of sound is:

dB = 10 log (I/K) ……… (i)

Where, K is the lowest threshold intensity of sound that a person can hear at 1000 Hz frequency and its value is 10^-12 W/m^2.

By putting values in equation (i),

19 = 10 log (I/10^-12)

Anti-log (1.9) = I/10^-12

I = (Anti-log (1.9))( 10^-12)

I = 7.94 × 10^-11 W/m^2

Answer 2

`10^(-10.1)`

Step-by-step explanation:

We know Intensity of sound is given by the formula

10㏒
`(I)/(K)`=D

(where I is intensity, K is a constant(K=
`10^(-12)`), and D is decibels)

by putting giving data in formula we get intensity(I)=
`10^(-10.1)`